Chapter 6
You have until Tuesday Nov. 26 to turn this assigment.
Is not in your not book, this is to be done in a seperate sheet of paper with your name.
Individual work.
Chapter 6
Stopping
distance and Kinematic Energy
Instructions:
Solve the
following problems according to the instruction of each. Show your work in the
space provide below each question. Round your answers to two decimals after the
period.
Assumptions:
The car is traveling is
straight line.
All conditions are
normal or optional
The car slows at a
constant acceleration of -5.0m/s2, when the breaks are applied under the above
conditions.
Suppose a
car is moving 11.2m/s. How far will it take the car to stop if it decelerates
at -5.0m/s2?
1. The car slows from 11.2 m/s to
0.0m/s; therefore, the average velocity will be:
2. To find the distance, you must find
the time interval, having that acceleration is equal to the division between the
velocity interval and the time interval, clear the formula for time interval.
3. Determinate the distance, using d=vavg
x Time interval
4. Complete the table for these
additional velocities
22.3m/s
33.5m/s
|
Velocity
|
Time (s)
|
Distance (m)
|
|
11.2m/s
|
|
|
|
22.3m/s
|
|
|
|
33.5m/s
|
|
|
5. Suppose that the car in the previous
problem has a mass of 2200Lbs. How much kinetic energy will it have a speed of
11.2m/s? (KE=1/2mv2)
6. Complete the table
|
Velocity
|
Kinetic Energy (J)
|
|
11.2m/s
|
|
|
22.3m/s
|
|
|
33.5m/s
|
|
7. Discussion questions:
a. Give two important driving
principles illustrated by this study.
b. Which of the assumptions is the most
unrealistic? Why?
c. List some factors discussed in the facet
on page 144 of your textbook that make one or more of these assumptions invalid
in the real world.
Thank you!
ResponderEliminar